# Explain why this is correct (Optimization Problem)

## Homework Statement

A piece of wire, 100 cm long, needs to be bent to form a rectangle. Determine the dimensions of a rectangle with the maximum area.

P = 2(l+w)
A = lw

## The Attempt at a Solution

This is what I don't understand, the solutions that I saw from looking around is:

l = x
w = (100 -2x) / 2

I don't understand why is width portrayed as shown above, and why the length is also potrayed as above, the solution goes onto:

A = (x)(100 - 2x / 2)
A = (x)(50 = x)
A = 50x - x^2
A prime = 50 - x^2
Insert 0 for A prime
0 = 50 - x^2
x=25
With therefore means the length and width are 25cm.

I understand the algebra, I do not understand how to get the length and width equation, wondering if someone could explain it to me.

Related Calculus and Beyond Homework Help News on Phys.org
Mark44
Mentor

## Homework Statement

A piece of wire, 100 cm long, needs to be bent to form a rectangle. Determine the dimensions of a rectangle with the maximum area.

P = 2(l+w)
A = lw

## The Attempt at a Solution

This is what I don't understand, the solutions that I saw from looking around is:

l = x
w = (100 -2x) / 2

I don't understand why is width portrayed as shown above, and why the length is also potrayed as above,
The 100 cm of wire will be the perimeter of the rectangle. From your formula for P, solve for the width w in terms of l. Also, introducing x as a variable is more complicating than just using w and l.
[IbrahimA said:
the solution goes onto:

A = (x)(100 - 2x / 2)
A = (x)(50 = x)
The first equation above is not written correctly. The second group in parentheses is 100 - 2x/2, which is properly interpreted as ##100 - \frac {2x} 2= 100 - x##. Obviously that's not what you meant, so the equation should have been written as A = x(100 - 2x)/2.

The second equation has a typo -- you wrote = instead of -.
[IbrahimA said:
A = 50x - x^2
A prime = 50 - x^2
Insert 0 for A prime
0 = 50 - x^2
x=25
With therefore means the length and width are 25cm.

I understand the algebra, I do not understand how to get the length and width equation, wondering if someone could explain it to me.

Simon Bridge
Homework Helper
Forget about the characteristic of length and width... a rectangle has two pairs of parallel sides... one pair has length x and the other has length y. Note the special case that x=y is allowed even though we said "rectangle".
If y>x then y is the length. If x>y then x is the length... but it does not matter to the maths, we can focus on either.

At this stage the x and y aee just labels... the next step uses maths to describe how these are related to the area and the perimeter. If the area is A and the perimeter is p, write down the equations for these in terms of x and y.

You need an ewuation for area in terms of only one other variable... so pick x or y, doesn't matter which, and make A depend only on that.

Note. Your final working contains two errors which cancel each other out... check the derivative.

Last edited: