I Unit Conversions of Force: How to Convert Between Different Units of Force?

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The discussion focuses on converting a force of 100 N into different units, specifically dg∙cm∙(ms)^−2. Participants clarify that "dg" refers to decigrams and discuss the conversion factors: 1 kg = 10,000 dg, 1 m = 100 cm, and 1 s = 1000 ms. The importance of using conversion factors that equal one is emphasized to maintain the value during the unit change. Additionally, the reciprocal nature of seconds to milliseconds in the context of Newton's units is explained. Understanding these conversions is crucial for accurate calculations in physics.
kokofaen
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TL;DR
Kg to dg, m to cm and s to ms
Hello.
Im studying for an exam and came across this simple unit conversion question but I haven't done something like this in a long time! I understand the conversions of each unit individually but get a bit stuck combining them. This is the question:

A force of 100 N is exerted on an object with the base units of Kg∙m∙(s)^-2
Express this in dg∙cm∙(ms)^−2

The answer:
100 dg∙cm∙(ms)^−2 = 1.0 x 10^2(dg∙cm∙(ms)^−2)

Could someone please explain why the converted answer is still simply 100 when the units have been converted to different degrees (e.g. 1kg =10,000 dg vs 1m =100cm)? Thank you!
 
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You also have to convert seconds to milliseconds.
 
Welcome to PF.

kokofaen said:
the units have been converted to different degrees
What is "dg" as a unit? Degrees? Decigrams? Something else?

Assuming from your equations that dg is decigrams, how many decigrams per kilogram? Remember that when converting units, one of the best ways is to just multiply through by terms that are "1" in value, but have both sets of units (the old ones and the new ones) expressed as a fraction. For example, if you want to convert some number of seconds to hours, you would do this:
$$7200 [seconds] = 7200 [seconds] \times 1 = 7200 [seconds] \frac{1 [hour]}{3600 [seconds]} = 2 [hour]$$
 
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berkeman said:
What is "dg" as a unit? Degrees? Decigrams? Something else?

Assuming from your equations that dg is decigrams, how many decigrams per kilogram? Remember that when converting units, one of the best ways is to just multiply through by terms that are "1" in value, but have both sets of units (the old ones and the new ones) expressed as a fraction. For example, if you want to convert some number of seconds to hours, you would do this:
$$7200 [seconds] = 7200 [seconds] \times 1 = 7200 [seconds] \frac{1 [hour]}{3600 [seconds]} = 2 [hour]$$
Hi, yes thank you for that.
The unit is decigrams.

So based on what you've said, would the working for this equation look like this:
1 kg = 10,000 dg
1 m = 100 cm
1 s = 1000 ms

Screenshot 2023-12-15 at 11.56.17 am.png


Also could I clarify that the reason the seconds and milliseconds are the reciprocal of the other units (which have the units converting TO as the numerator and FROM as the denominator) is because the units for newtowns are S^-2 or ms^-2 respectively?
 
Ĺ
kokofaen said:
Hi, yes thank you for that.
The unit is decigrams.

So based on what you've said, would the working for this equation look like this:
1 kg = 10,000 dg
1 m = 100 cm
1 s = 1000 ms

View attachment 337223

Also could I clarify that the reason the seconds and milliseconds are the reciprocal of the other units (which have the units converting TO as the numerator and FROM as the denominator) is because the units for newtowns are S^-2 or ms^-2 respectively?
If a particle moves at ##1m/s##, then that is only ##0.001 m## per millisecond. Or ##1## millimeter per millisecond. ##1 m/s## is certainly not the same as ##1km## per millisecond.
 
I have been insisting to my statistics students that for probabilities, the rule is the number of significant figures is the number of digits past the leading zeros or leading nines. For example to give 4 significant figures for a probability: 0.000001234 and 0.99999991234 are the correct number of decimal places. That way the complementary probability can also be given to the same significant figures ( 0.999998766 and 0.00000008766 respectively). More generally if you have a value that...

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