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Unitary Operation On A Complex Matrix

  1. Dec 18, 2014 #1
    Hello everyone,

    Let ##A = (\alpha_{ij})## be an $n \times n# complex matrix. Define ##\hat## acting on ##A## as producing the matrix ##\hat{A} = (\alpha_{ij} I_n)##.

    I don't understand what this is saying. Isn't ##I_n## the identity matrix, and therefore the product of it with any matrix results in the other matrix? If this is so, wouldn't ##\hat{A} = (\alpha_{ij} I_n) = (\alpha_{ij}) = A##?
     
  2. jcsd
  3. Dec 18, 2014 #2

    FactChecker

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    Without seeing more of the context, I would think that ##\hat{A}## is an n2 by n2 matrix where every element, ##\alpha_{ij}##, of A is replaced by the n by n submatrix ##\alpha_{ij}I_n##
     
    Last edited: Dec 18, 2014
  4. Dec 19, 2014 #3

    Fredrik

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    ##\alpha_{ij}## isn't a matrix.

    The notation in the sentence you're asking about is very strange. If ##(\alpha_{ij})## denotes the matrix with ##\alpha_{ij}## on row i, column j, then ##(\alpha_{ij}I_n)## should denote the matrix with ##\alpha_{ij}I_n## on row i, column j. But this is a matrix whose every component is a matrix. Is it possible that this is what they meant? If yes, then I agree with FactChecker. If no, then maybe they meant ##\hat A=(\alpha_{ij}(I_n)_{ij}) =(\alpha_{ij}\delta_{ij})##.
     
    Last edited: Dec 19, 2014
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