Universal Gravitation and a satellite

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SUMMARY

The discussion focuses on calculating the gravitational force exerted by Earth on a satellite with a mass of 4600 kg and an orbital period of 5500 seconds. Using Kepler's Equation and the gravitational force formula, the user attempted to find the radius of the satellite's orbit. The calculations led to an incorrect value for the gravitational force, indicating a misunderstanding in the application of the cube root to the radius. The correct approach requires taking the cube root of R^3 to obtain R, which is essential for accurate force calculations.

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  • Understanding of Newton's Law of Universal Gravitation
  • Familiarity with Kepler's Laws of planetary motion
  • Knowledge of gravitational force equations, specifically Fg = GmM/R^2
  • Ability to manipulate and solve algebraic equations involving exponents and roots
NEXT STEPS
  • Study the derivation and application of Kepler's Third Law in orbital mechanics
  • Learn about the gravitational constant G and its significance in astrophysics
  • Explore advanced topics in orbital dynamics, including perturbations and non-circular orbits
  • Practice solving problems involving gravitational forces and satellite motion using real-world examples
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Students in physics or engineering, educators teaching gravitational concepts, and anyone interested in satellite dynamics and orbital mechanics.

Bowenj
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Homework Statement


A satellite of mass 4600 kg orbits the Earth (mass = 6.0 1024 kg) and has a period of 5500 s.
(a) Find the magnitude of the Earth's gravitational force on the satellite.
(b) Find the altitude of the satelite


Homework Equations



Kepler's Equation: R^3/T^2

Fg= GmM/R^2

Fc= m4pi^2R/T^2




The Attempt at a Solution



I tried setting Fc= Fg and solving for R. So it ended up being

R^3= GmT^2/(4pi^2)

I plugged the numbers in...

R^3= (6.67e-11)(6e24)(5500)^2/(4pi^2)

so then i solved and took the cube root and got 3.07e20 and plugged that back into the Fg equation so it was

Fg= GmM/R^2

Fg=(6.67e-11)(4600)(6e24)/(3.07e20)^2

which was like... 2.95e-23...? and I'm pretty sure that isn't right...
 
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Fc = m ( omega R)^2 /( R)
Fc= m (2 pi)^2 R / (T^2)
Fg= G M m /R^2

Fc=Fg
R^3 = GM T^2/ (2 pi)^2
no problem
 
Last edited:
Bowenj said:
R^3= GmT^2/(4pi^2)

I plugged the numbers in...

R^3= (6.67e-11)(6e24)(5500)^2/(4pi^2)

so then i solved and took the cube root and got 3.07e20

Those expressions are correct, but 3.07e20 is R3, not R. If you actually take the cube root, you should find the correct answer for the gravitational force.
 

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