Universal gravitational, elliptical orbits

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
3 replies · 3K views
carbon_mc
Messages
6
Reaction score
0

Homework Statement


a spacecraft of mass 1000kg, in an elliptical orbit about the earth, at one point its distance from Earth is 1.2 x 107 meters and its velocity is 7.1 x 103 meters per sec, and the velocity vector is perpendicular to the line connecting the center of the Earth to the spacecraft . Mass of Earth is 6.0 x 1024 kg and radius of Earth is 6.4 x 106
Find the magnitude of the angular moemntum of the spacecraft about the center of the earth


Homework Equations



L = I [tex]\omega[/tex]
L = r x p
[tex]\omega[/tex] = v/r

The Attempt at a Solution



ok so I know that energy and angular momentum is conserved. I know how to solve this but I just want to make sure. Do I just do this by finding the angular velocity by [tex]\omega[/tex] = v/r then multiplied by I which equals to mr2 . it sounds really weird so I just want to make sure.
 
Physics news on Phys.org
Just use L=rxp. What's the length of r, the length of p and the angle between them?
 
I think it's mvr .. they didnt say anything about angle or anything. the velocity vector is perpendicular so it's sin 90 = 1 .
 
so you shoul have all the info for L = r x p, which becomes |L| = r(mv).sin(theta) = r(mv) = mvr, when the velocity & position vector are perpindicular