Update To My Problem On Vectorcalculus

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A particle moves in a circle that is centered at the origin. The particle has position r and angular velocity w. The velocity v is given by:

v = w x r (with x = the cross product).

My question is, when I calculate this crossproduct with

w= (d(theta)/dt) k and
r= x i + y j + z k

it gives:

(d(theta)/dt) * x j - (d(theta)/dt) * yi

Why does this denote the velocity?
 
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Compute its modulus and see whether you can find

[tex]|\vec{v}|=\frac{d\theta (t)}{dt} R[/tex]

,where R is the circle's radius.

Daniel.

BTW, you can check whether that vector is always tangent to the circle by dotting it with [itex]\vec{r}[/itex].
 
Thanks I get it now :)