- #1

Rosalie

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The problem is stated as follows:

You have an urn with 12 red balls, 20 green balls, and 13 yellow balls. Suppose 3 balls are drawn

I am pretty sure I use Bayes formula, but I am not certain how to apply it in this case. I am really just baffled! Can anyone help me?

You have an urn with 12 red balls, 20 green balls, and 13 yellow balls. Suppose 3 balls are drawn

*without*replacement. What is the probability the third ball is yellow given the first ball is green.I am pretty sure I use Bayes formula, but I am not certain how to apply it in this case. I am really just baffled! Can anyone help me?

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