Use Conservation of Momentum or Conservation of KE for spring problem

In summary, the system shown has a spring attached to two masses, with Mass I being 3 times greater than Mass II. The spring is initially stretched and released, causing the masses to approach each other. The same for both masses is the conservation of momentum, as this is a closed system with no energy lost or gained and a perfectly elastic collision. The problem is asking about the kinetic energy and momentum of each mass individually, not the combined total.
  • #1
brainyasian
13
0

Homework Statement



The system shown above has a spring attached to two masses. Mass I is 3 times greater in mass than Mass II. The spring is initially stretched and let go to allow the two masses to approach each other. Which of the following is the same for both masses?
a. speed
b. velocity.
c. acceleration
d. kinetic energy
e. magnitude of momentum

Homework Equations


Conservation of momentum
conservation of energy


The Attempt at a Solution


I know it's not the first three, but I'm not sure if you use the conservation of momentum or the conservation of energy for this problem
 
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  • #2
Try proving each one and post what you get here.

What would cause momentum to be lost?
 
  • #3
Screen said:
Try proving each one and post what you get here.

What would cause momentum to be lost?

But this is a closed system. Since no energy is lost or gained and this is a perfectly elastic collision, wouldn't both KE and momentum remain the same afterwards?
 
  • #4
brainyasian said:
But this is a closed system. Since no energy is lost or gained and this is a perfectly elastic collision, wouldn't both KE and momentum remain the same afterwards?

Try writing it mathematically.

The problem is asking about the kinetic energy and momentum of each mass, not the combined total.
 
  • #5
Screen said:
Try writing it mathematically.

The problem is asking about the kinetic energy and momentum of each mass, not the combined total.

but doesn't KE(M1) = KE(M2) because of conservation of mass and doesn't M(A)V(A) = M(B)V(B) make momentum equal?
 
  • #6
brainyasian said:
but doesn't KE(M1) = KE(M2) because of conservation of mass and doesn't M(A)V(A) = M(B)V(B) make momentum equal?

Read the question carefully; they haven't collided yet.
 

1. How do I determine if conservation of momentum or conservation of kinetic energy should be used for a spring problem?

The choice between using conservation of momentum or conservation of kinetic energy for a spring problem depends on the specific scenario and what information is known. If the mass and velocity of the object before and after the spring is used, conservation of momentum would be the appropriate choice. However, if the spring constant and displacement of the object are known, conservation of kinetic energy would be more suitable.

2. Can conservation of momentum and conservation of kinetic energy be used interchangeably for a spring problem?

No, conservation of momentum and conservation of kinetic energy are two separate principles that cannot be used interchangeably. While both involve the conservation of a physical quantity, they are based on different variables and have different equations.

3. How is the conservation of momentum applied to a spring problem?

In a spring problem, conservation of momentum is applied by equating the momentum of the object before the spring (initial momentum) to the momentum of the object after the spring (final momentum). This takes into account any external forces acting on the object and the change in velocity due to the spring's force.

4. Is conservation of kinetic energy always applicable for a spring problem?

No, conservation of kinetic energy is not always applicable for a spring problem. This principle only applies when there are no external forces acting on the object and the kinetic energy of the system is conserved. If there are external forces, such as friction, then the kinetic energy of the system will not be conserved and conservation of kinetic energy cannot be used.

5. Can conservation of momentum and conservation of kinetic energy be used simultaneously for a spring problem?

Yes, conservation of momentum and conservation of kinetic energy can both be used simultaneously for a spring problem. This would involve setting up and solving a system of equations to take into account both principles and any external forces acting on the object. This method may be necessary for more complex spring problems where both principles are applicable.

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