Use Conservation of Momentum or Conservation of KE for spring problem

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Homework Help Overview

The problem involves a system with two masses connected by a spring, where one mass is three times greater than the other. The scenario examines the conditions of motion as the spring is released, prompting questions about the conservation of momentum and kinetic energy.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the applicability of conservation laws, questioning whether momentum or kinetic energy remains constant for each mass. There are attempts to analyze the implications of a closed system and elastic collisions.

Discussion Status

There is an ongoing exploration of the relationships between kinetic energy and momentum for each mass, with participants suggesting mathematical formulations. Some participants express uncertainty about the conditions under which these quantities are equal or conserved.

Contextual Notes

Participants note that the problem specifies the scenario before the masses collide, which raises questions about the definitions and assumptions regarding kinetic energy and momentum in this context.

brainyasian
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Homework Statement



The system shown above has a spring attached to two masses. Mass I is 3 times greater in mass than Mass II. The spring is initially stretched and let go to allow the two masses to approach each other. Which of the following is the same for both masses?
a. speed
b. velocity.
c. acceleration
d. kinetic energy
e. magnitude of momentum

Homework Equations


Conservation of momentum
conservation of energy


The Attempt at a Solution


I know it's not the first three, but I'm not sure if you use the conservation of momentum or the conservation of energy for this problem
 
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Try proving each one and post what you get here.

What would cause momentum to be lost?
 
Screen said:
Try proving each one and post what you get here.

What would cause momentum to be lost?

But this is a closed system. Since no energy is lost or gained and this is a perfectly elastic collision, wouldn't both KE and momentum remain the same afterwards?
 
brainyasian said:
But this is a closed system. Since no energy is lost or gained and this is a perfectly elastic collision, wouldn't both KE and momentum remain the same afterwards?

Try writing it mathematically.

The problem is asking about the kinetic energy and momentum of each mass, not the combined total.
 
Screen said:
Try writing it mathematically.

The problem is asking about the kinetic energy and momentum of each mass, not the combined total.

but doesn't KE(M1) = KE(M2) because of conservation of mass and doesn't M(A)V(A) = M(B)V(B) make momentum equal?
 
brainyasian said:
but doesn't KE(M1) = KE(M2) because of conservation of mass and doesn't M(A)V(A) = M(B)V(B) make momentum equal?

Read the question carefully; they haven't collided yet.
 

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