Use logarithmic differentiation to find the derivative

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Logarithmic differentiation is useful when both the base and exponent contain variables, particularly for complex functions. The discussion highlights a mistake in applying the chain rule during differentiation, specifically in the expression ln y = (1/2) ln(x^2 + x). While the final answer for the derivative was correct, several intermediate steps contained errors. It is suggested that simpler functions can often be differentiated directly using the chain rule instead of logarithmic differentiation. Overall, understanding when to use logarithmic differentiation is key to solving such problems effectively.
manal950
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Hi ..


Use logarithmic differentiation to find the derivative

647224042.jpg


can please check my answer and How I can know if the question want answer by using logarithmic differentiation or not ?
 
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manal950 said:
Hi ..


Use logarithmic differentiation to find the derivative

647224042.jpg


can please check my answer and How I can know if the question want answer by using logarithmic differentiation or not ?

In your 4th line you have a mistake.
Your 3rd line is:
ln y = (1/2) ln(x2 + x)

When you differentiate the left side, you should get (1/y) y', due to the chain rule.

In your last line a factor of y seems to have magically popped up on the right side. You got the right value for the derivative, but several steps in between are incorrect.
 
manal950 said:
Hi ..

Use logarithmic differentiation to find the derivative

647224042.jpg


can please check my answer and How I can know if the question want answer by using logarithmic differentiation or not ?
Answer is correct, but as Mark pointed out there are some errors along the way.

It could be simplified. You have \ \sqrt{x^2+x}\ in the numerator and x2 + x in the denominator.

If you have x in an exponent and also have x in the base, then logarithmic differentiation can be helpful.

The function you are differentiating here can be done more easily by simply applying the chain rule.
 
You usually use logarithmic differentiation when the exponent is also a variable.

BiP
 
thanks so much ...
 
can check this answer please

828239533.jpg
 
manal950 said:
can check this answer please

828239533.jpg
You really should start a new thread for this.

The 1/3 multiplies both logarithms .
 
thansk
 

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