MHB Use midpoint rule to estimate the average velocity?

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To estimate the average velocity of a car during the first 12 seconds using the midpoint rule, the formula involves calculating the integral of the velocity function over the interval. The average velocity is expressed as \(\overline{v}(t)=\frac{1}{12}\int_0^{12}v(t)\,dt\). By applying the midpoint rule with three sub-intervals, the integral can be approximated as \(4(v(2) + v(6) + v(10))\). The necessary velocity values can be obtained from the provided graph. This approach effectively utilizes the midpoint rule to estimate the average velocity.
shamieh
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Use the midpoint rule to estimate the average velocity of the car during the first 12 seconds.

Click here to see the graph from my book.

i understand the midpoint rule is
$$\frac{b - a}{n}$$

so $$\frac{12}{4} = 3$$
so $$n = 3$$

I also know that

$$\frac{1}{12} \int^{12}_{0} v(t)dt $$

But now I'm stuck... any guidance anyone can offer would be great.
 
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The average velocity would be given by (as you stated):

$$\overline{v}(t)=\frac{1}{12}\int_0^{12}v(t)\,dt$$

Using the Midpoint rule to approximate the integral in this expression, with 3 sub-intervals of equal width ($n=3$), we could state:

$$\int_0^{12}v(t)\,dt\approx\frac{12-0}{3}\sum_{k=1}^3\left(v\left(2(2k-1) \right) \right)=4\left(v(2)+v(6)+v(10) \right)$$

Do you see that we evaluate the velocity function at the midpoint of each sub-interval?

Now you just need to read the needed values from the given graph.
 
There are probably loads of proofs of this online, but I do not want to cheat. Here is my attempt: Convexity says that $$f(\lambda a + (1-\lambda)b) \leq \lambda f(a) + (1-\lambda) f(b)$$ $$f(b + \lambda(a-b)) \leq f(b) + \lambda (f(a) - f(b))$$ We know from the intermediate value theorem that there exists a ##c \in (b,a)## such that $$\frac{f(a) - f(b)}{a-b} = f'(c).$$ Hence $$f(b + \lambda(a-b)) \leq f(b) + \lambda (a - b) f'(c))$$ $$\frac{f(b + \lambda(a-b)) - f(b)}{\lambda(a-b)}...

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