Use quadratic formula to solve a function

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SUMMARY

The discussion centers on the application of the quadratic formula to solve for Lambda1 and Lambda2 in the equation L-1(1-(Lambda1+Lambda2)L+Lambda1Lambda2L2)Ft. Participants clarified that the original expression lacks an equality sign, thus it does not constitute a solvable equation. The user initially assumed L1=Lambda1 and L2=Lambda2, but encountered discrepancies when substituting these values back into the expression. The consensus emphasizes the necessity of having a proper equation to apply the quadratic formula effectively.

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Kinetica
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Homework Statement



L-1(1-(Lambda1+Lambda2)L+Lambda1Lambda2L2)Ft

Use quadratic formula to solve for Lambda1 and Lambda2


The Attempt at a Solution



I took the equation inside the brackets and solved for L. It turned out that
L1=Lambda1 and L2=Lambda2

But when I plugged those findings back, I got a slightly different equation. Weird...

Anyway, is that a right approach or am I missing something? You can see my full solution in the attachment.

Thanks A LOT!
 

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Kinetica said:

Homework Statement



L-1(1-(Lambda1+Lambda2)L+Lambda1Lambda2L2)Ft

Use quadratic formula to solve for Lambda1 and Lambda2
What you have is not an equation, so you can't solve for anything.
Kinetica said:

The Attempt at a Solution



I took the equation inside the brackets and solved for L.
An equation has an = in it. That's how you know it's an equation. You don't have an equation.
Kinetica said:
It turned out that
L1=Lambda1 and L2=Lambda2

But when I plugged those findings back, I got a slightly different equation. Weird...

Anyway, is that a right approach or am I missing something? You can see my full solution in the attachment.

Thanks A LOT!
 

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