Use the properties of logarithma to xpand the logarithmic function

[Ki-nana18]

Homework Statement

Use the properties of logarithma to xpand the logarithmic function ln[(x²+1)(x-1)]

Homework Equations

The Attempt at a Solution

[ln x²+ln 1]+[ln x-ln 1]
2 ln x+ln x

 

[gamer_x_]

the first step makes sense: $$ln[(x^2+1)(x-1)]=ln(x^2+1)+ln(x-1)$$

but then you continued: $$ln(x^2+1)=ln(x^2)+ln(1)$$

You can't do that, but you can do something else to the $$x^2+1$$...

 

[Mark44]

the first step makes sense: $$ln[(x^2+1)(x-1)]=ln(x^2+1)+ln(x-1)$$

but then you continued: $$ln(x^2+1)=ln(x^2)+ln(1)$$

You can't do that, but you can do something else to the $$x^2+1$$...

Is the something else you're thinking about factoring x^2 + 1?

 

[gamer_x_]

I just realized I was stupidly thinking of $$x^2-1$$ not $$x^2+1$$. You can't really factor that term unless you go into imaginary numbers.

 

[Mark44]

That's what I thought you might be thinking.