Use the properties of logarithma to xpand the logarithmic function ln[(x2+1)(x-1)]
The Attempt at a Solution
[ln x2+ln 1]+[ln x-ln 1]
2 ln x+ln x
Is the something else you're thinking about factoring x^2 + 1?the first step makes sense: [tex]ln[(x^2+1)(x-1)]=ln(x^2+1)+ln(x-1)[/tex]
but then you continued: [tex]ln(x^2+1)=ln(x^2)+ln(1)[/tex]
You can't do that, but you can do something else to the [tex]x^2+1[/tex]...