Undergrad Using 4-derivative

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The discussion focuses on the mathematical properties of the derivative operator ##\partial^\mu## and its application to the coordinate ##x_\nu##. The user derives that applying ##\partial^\mu## to ##x_\nu## results in ##\partial^\mu x_\nu = \delta_\nu^\mu##, indicating that the operation yields the identity matrix. There is a mention of the relationship between the metric tensor ##\eta## and the derivatives, with the user expressing their understanding through matrix representation. A comment suggests that while the derivations are correct, both ##\partial^\mu## and ##x_\mu## are considered less natural than their counterparts ##\partial_\mu## and ##x^\mu##. The discussion concludes with a preference for explicitly writing out the metric for clarity.
deuteron
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Hi! I am trying to understand the object ##\partial^\mu##, and wanted to check if the result I am getting below is true.

The definition of ##\partial_\mu## is:

$$\partial_\mu = ( \frac \partial {\partial x^0} , \frac \partial {\partial x^1}, \frac \partial {\partial x^2},\frac \partial {\partial x^3})$$

We define ##\partial^\mu## as:

$$\partial^\mu = \eta^{\mu\nu}\partial_\nu = (\frac \partial {\partial x^0} , -\frac\partial {\partial x^1} , -\frac \partial {\partial x^2}, -\frac \partial {\partial x^3})$$

In this case, if we were to apply ##\partial^\mu## to ##x_\nu##, we would get:

$$\partial^\mu x_\nu = (\eta^{\mu\rho}\partial_\rho)x_\nu=\eta^{\mu\rho} \partial_\rho (\eta_{\nu\sigma} x^\sigma)$$

Since ##\eta##'s are just number, I rearrange the equation to be:

$$=\eta^{\mu\rho} \eta_{\nu\sigma} \partial_\rho x^\sigma$$

Here, my knowledge of indices and contraction ends and I try to think of the objects like matrices, in which case I write:

$$= \begin{bmatrix} 1&0&0&0\\ 0&-1&0&0\\0&0&-1&0\\0&0&0&-1\end{bmatrix}\begin{bmatrix} 1&0&0&0\\ 0&-1&0&0\\0&0&-1&0\\0&0&0&-1\end{bmatrix} \begin{bmatrix} \frac {\partial x^0}{\partial x^0} & \frac {\partial x^1}{\partial x^0} & \frac {\partial x^2}{\partial x^0} & \frac {\partial x^3}{\partial x^0} \\ \frac {\partial x^0}{\partial x^1} & \frac {\partial x^1}{\partial x^1} & \frac {\partial x^2}{\partial x^1} & \frac {\partial x^3}{\partial x^1}\\ \frac {\partial x^0}{\partial x^2} & \frac {\partial x^1}{\partial x^2} & \frac {\partial x^2}{\partial x^2} & \frac {\partial x^3}{\partial x^2} \\ \frac {\partial x^0}{\partial x^3} & \frac {\partial x^1}{\partial x^3} & \frac {\partial x^2}{\partial x^3} & \frac {\partial x^3}{\partial x^3}\end{bmatrix} $$

Here, one can observe the last matrix reduces to the identity matrix, and the multiplication of two ##\eta##'s also reduces to the identity matrix, thus I get:

$$=\mathbb I$$

Are these steps correct?
 
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It seems OK.
\partial^\mu x_\nu = \delta_\nu^\mu
 
It looks ok. I would only comment that both ##\partial^\mu## and ##x_\mu## are somewhat artificial objects compared to the more natural ##\partial_\mu## and ##x^\mu##.

I much prefer actually writing out the metric.
 
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Likes SiennaTheGr8, deuteron and dextercioby
MOVING CLOCKS In this section, we show that clocks moving at high speeds run slowly. We construct a clock, called a light clock, using a stick of proper lenght ##L_0##, and two mirrors. The two mirrors face each other, and a pulse of light bounces back and forth betweem them. Each time the light pulse strikes one of the mirrors, say the lower mirror, the clock is said to tick. Between successive ticks the light pulse travels a distance ##2L_0## in the proper reference of frame of the clock...

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