Using a while loop to print the counting numbers up to a set value

[needOfHelpCMath]

Write a while loop that prints 1 to userNum, using the variable i. Follow each number (even the last one) by a space. Assume userNum is positive. Ex: userNum = 4 prints:
1 2 3 4

#include <iostream>
using namespace std;

int main() {
   int userNum = 0;
   int i = 0;

   userNum = 4;    // Assume positive
   
   
while ( userNum > i) {
cout << userNum << " ";
userNum = userNum - 1;
}

   cout << endl;

   return 0;
}

Run
✖ Testing with userNum = 4
Expected output: 1 2 3 4
Your output: 4 3 2 1

 

[MarkFL]

Re: What i am doing wrong?

You need to use [m]i[/m] to "index" your while loop, which should run as it is less than or equal to [m]userNum[/m]. Since [m]i[/m] is initialized to zero, you will want to increment it before the comparison, using [m]++i[/m], and then you will not need to increment it within the loop, you will only need to print its value along with the trailing space.

 

[needOfHelpCMath]

Re: What i am doing wrong?

You need to use [m]i[/m] to "index" your while loop, which should run as it is less than or equal to [m]userNum[/m]. Since [m]i[/m] is initialized to zero, you will want to increment it before the comparison, using [m]++i[/m], and then you will not need to increment it within the loop, you will only need to print its value along with the trailing space.

"Awesome To The Max"