Using moment of inertia to get angular speed

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SUMMARY

The discussion focuses on calculating the angular speed of a uniform rod after its length is reduced due to a catch slipping. The initial angular speed is given as 0.0500 radians per second, and the rod's length changes from 3.00 meters to 1.50 meters. The moment of inertia equations used are I = mr²/12 and I = mr²/3. The conservation of angular momentum principle is applied, leading to the equation Iinitial = Ifinal to find the new angular speed after the catch slips.

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seiya5
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Homework Statement



Hiya boys,

Sorry i don't know how to proceed with this problem can anyone help me solve these two questions?

In preparation for building a space station, an astronaut removes a self-telescoping uniform rod from the cargo bay and releases it, not noticing that he gave it an angular speed of 0.0500 radians per second. The pole is 3.00 meters long. A catch slips, and the pole spring retracts it into a shorter 1.50 meter long uniform pole about a minute after the astronaut releases it.
Find the angular speed after the catch slips.

Homework Equations



I = mr^2/12 or mr^2/3

ω = v/r

The Attempt at a Solution



Iinitial = Ifinal
m (3^2)/12 = m (1.5^2)/12

m= do i need this?

(0.05)(x) = ω
 
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seiya5 said:
Iinitial = Ifinal
m (3^2)/12 = m (1.5^2)/12

What are Iinitial and Ifinal here? The eqn can't be right since it reduces to 4 = 1.
 

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