Variation of quadratic Riemann Curvature tensor

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SUMMARY

The discussion centers on the variation of the quadratic Riemann curvature tensor, specifically how to manipulate the indices in the context of general relativity. The user references the Lagrangian from Ray d'Inverno's textbook, which includes terms involving the Riemann tensor and metric tensor. The user expresses frustration over not being able to derive the correct variation despite extensive attempts. Key expressions discussed include the Lagrangian \(L_{uv} = \sqrt{-g}[g_{ud}R^{abcd}R_{abcv} + g_{vd}R^{abcd}R_{abcu} - \frac {1}{2}g_{uv}R^{abcd}R_{abcd}]\) and its simplified form \(L_{uv} = \sqrt{-g}[2R_{uv} - \frac {1}{2}g_{uv}R]\).

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Qatawna blitz
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TL;DR Summary: How can I variate the quadratic Riemann curvature tensor, I tried raising and lowering the indices.

Hi,
Can you help me with this variation, I tried raising and lowering the indices.
1732356039421.png


I tried for months every possible method to reach the following answer without success.

1732356173162.png
 
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Please provide the reference if you want people to help. Your Langrangian suddenly contains two indices u and v, and my crystal ball provides no information about what that means.
 
I think the two indicies uv in the answered lagrangian means variation with respect to guv
It's in the textbook: Introducing Einstein's General Relativity "Ray d'Inverno" @haushofer
 
Hi.

##L_{uv} = \sqrt{-g}[g_{ud}R^{abcd}R_{abcv} + g_{vd}R^{abcd}R_{abcu} - \frac {1}{2}g_{uv}R^{abcd}R_{abcd}]##

I could be wrong but it looks like following expression:

##L_{uv} = \sqrt{-g}[2R_{uv} - \frac {1}{2}g_{uv}R]##
 
Qatawna blitz said:
TL;DR Summary: How can I variate the quadratic Riemann curvature tensor, I tried raising and lowering the indices.

Hi,
Can you help me with this variation, I tried raising and lowering the indices.
View attachment 353814

I tried for months every possible method to reach the following answer without success.

View attachment 353815
Can you post a screenshot with the full problem description?
 
Moderator's note: Thread moved to the advanced physics homework help forum.
 
Qatawna blitz said:
I tried for months every possible method to reach the following answer without success.
Please post what you have tried.
 
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