Vector Basics: Finding V1 and V2 | Homework Statement and Equations

  • Thread starter Thread starter jrm2002
  • Start date Start date
  • Tags Tags
    Basics Vector
Click For Summary
SUMMARY

The discussion focuses on determining the vector V1, which is parallel to the xz plane, given that vector V2 is perpendicular to V1 and has a magnitude of 10 units. It is established that while the direction of V1 can be derived using the cross product of V2 and the normal vector V3=(0,1,0), the magnitude of V1 cannot be determined without additional information about V2. The cross product V2 x V3 results in a vector that lies in the xz plane and is perpendicular to V2. If V2 is parallel to V3, the cross product evaluates to the zero vector, indicating no area is formed between the vectors.

PREREQUISITES
  • Understanding of vector operations, specifically cross products
  • Familiarity with vector notation and components (e.g., V2=(x,y,z))
  • Knowledge of geometric interpretations of vectors in three-dimensional space
  • Basic principles of linear algebra related to vector magnitudes and directions
NEXT STEPS
  • Study the properties of the cross product in vector mathematics
  • Learn about vector projections and their applications in physics
  • Explore the geometric interpretation of vectors in three-dimensional space
  • Investigate the implications of parallel vectors in vector calculus
USEFUL FOR

Students studying physics or mathematics, particularly those focusing on vector analysis and geometric interpretations in three-dimensional space.

jrm2002
Messages
54
Reaction score
0

Homework Statement



I have two vectors V1 and V2.
V1 is parallel to xz plane
V2 is perpendicular to V1
V2 is 10 units.Can i get V1?

Homework Equations





The Attempt at a Solution



Force triangle?Can''t solve?
 
Physics news on Phys.org
You can only get V1's direction, not magnitude.
 
How can we get the direction of V1?
 
The normal to the xz plane is the vector V3=(0,1,0). If V1 is parallel to the xz plane then it is perpendicular to V3. So V1 is perpendicular to V2 and V3. So a direction for V1 is given by the vector cross product of V2xV3.
 
But from the given conditions, v2 (only the magnitude is known) is not given, how can you know v1's direction ?
 
The direction is the same as v2x(0,1,0). That's about all you can say. And if v2 is parallel to (0,1,0) then you can't say much of anything at all.
 
You said:
what will be the value of cross product V2 x V3?
 
My question:

what will be the value of cross product V2 x V3?
 
jrm2002 said:
My question:

what will be the value of cross product V2 x V3?

Ok, shorter answer. NO. You can't 'get' V1.
 
  • #10
But what will be the cross product V2 x V3, in an expression?
 
  • #11
If V2=(x,y,z), (x,y,z)x(0,1,0)=(-z,0,x) (look up cross product). The result is in the xz plane is perpendicular to V2.
 
  • #12
Plz help with another case:

1. If V2 and V3 are parallel
2. Hence V1 = the cross product of V2 x V3 evaluates to 0,0,0
3. What is the physical reason for this?
 
  • #13
The cross product is related to the area of the parallelogram created by the two vectors. What happens if they are parallel?
 
  • #14
Straight line?
 
  • #15
If you mean what I think you mean then yes. The area is zero. So the vector is zero.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
11K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
721
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 79 ·
3
Replies
79
Views
7K
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K