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mkematt96
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Homework Statement
Homework Equations
I(t) = E/R [ 1 - e^-t/tau)] Vseries = Sum of voltages , Vparalel= V1=V2=V3... V=I*R
I think I'd get in trouble if I told you this before you've sorted it out by your own way.mkematt96 said:If YOU were doing this problem how would you start it?
The top of R1 is joined to the top of R2, but the bottom of R1 is not connected to the bottom of R2, (whether the switch is open or closed), so I'd say they are not in parallel.mkematt96 said:So the two resistors aren't in parallel when the switch is closed?
BTW I had to use Resistance in parallel for the I(t) equation.mkematt96 said:I I re did my calculations and found I(t) for the circuit at time stated. I then used Kirchoffs loop rule for the outter loop : 12 V - R2*I(t) -L di/dt = 0
So 12 V - R2* I(t) = L di/dt = V(L) which gave me the correct answer of 9.9 Volt.
An inductor is an electrical component that stores energy in the form of a magnetic field. It consists of a coil of wire that resists changes in current flow, creating a voltage drop across it.
The voltage across an inductor increases as the current flowing through it increases, and decreases as the current decreases. In a DC circuit, the voltage across an inductor reaches its maximum value when the current is at its maximum, and drops to zero when the current is at zero.
The voltage across an inductor is affected by the inductance of the component, the current flowing through it, and the rate at which the current changes. The higher the inductance and current, the higher the voltage across the inductor will be. Similarly, a faster rate of change in current will result in a higher voltage across the inductor.
The voltage across an inductor is calculated using the formula V = L di/dt, where V is the voltage, L is the inductance, and di/dt is the rate of change of current with respect to time.
Yes, the voltage across an inductor can be negative in a DC circuit if the current is decreasing at a fast rate. This is because the voltage across an inductor is proportional to the rate of change of current, so a rapidly decreasing current can result in a negative voltage across the inductor.