A dog walks 3.50m south, then 8.20m at an angle 39.4 degrees north of east, and finally 15.0m west. a) What is the magnitude of the dog's total displacement b) What is the directionof the dog's total displacement where directly east is taken as zero degrees and counter-clockwise is positive? I have found components of some of the vectors Ax= 0 Ay= -3.50 Bx= 15? (I am not sure about this) By= -3.50 Cy= 0 Is Cx = 15? Then I used the formula C= sqrt Cx^2 + Cy^2 Resulting in 15 meters as the magnitude of displacement. Which doesn't sound right to me since he must have passed his starting point along his route of 15 meters west. I then Used the formula tan -1 (Cy/Cx) resulting in 0 for his direction. Can someone please help?!?