Vector Identity (del operator)

[racnna]

i am completely lost as to how to go from
$$p^ \frac{1}{m}∇p$$
to
$$\frac{m}{m+1} ∇p^\frac{m+1}{m}$$

 

[Muphrid]

In general, the chain rule should tell you that,

$$\nabla p^a = a p^{a-1} \nabla p$$

Choose an appropriate value for $a$ and see what happens.

 

[racnna]

oh wow...nice trick