Vector Space Solutions for Systems: Explained Here

Click For Summary
A solution set for a system is not generally a vector space unless it meets specific criteria. It is not closed under scalar multiplication, which is a requirement for vector spaces. In cases of unique solutions, only the zero vector constitutes the vector space. However, the solution set of a system of homogeneous equations forms a subspace. If the system has fewer independent equations than unknowns, it results in a non-trivial subspace of R^n.
EvLer
Messages
454
Reaction score
0
Hi everyone,
general question: is a solution set for a particular system a vector space? I know it can be if there is a unique solution, but is it generally true?
Could someone explain, please?

Thanks.
 
Physics news on Phys.org
No. Vector spaces are closed under scalar multiplication. If b is a scalar not equal to 1, Y is non-zero, and X is a solution of AX = Y, then:

A(bX) = b(AX) = bY is not equal to Y, so (bX) is not a solution, so the set of solutions is not closed under scalar multiplication, so the set of solutions is not a vector space. Perhaps I've misinterpreted your question. If there is a unique solution, then there would only be that 1 element of the vector space. The only vector space that has only one element is the degenerate vector space {0}.
 
For a particular system? Do you mean a system of linear equations?

The solution set of a system of homogenous equations is a subspace.

If the system consists of n independent equations in n unknowns, then it is just the 0 vector but if the rank is lower than the number of unknowns, then it is a non-trivial subspace of Rn[/sub].
 
I am studying the mathematical formalism behind non-commutative geometry approach to quantum gravity. I was reading about Hopf algebras and their Drinfeld twist with a specific example of the Moyal-Weyl twist defined as F=exp(-iλ/2θ^(μν)∂_μ⊗∂_ν) where λ is a constant parametar and θ antisymmetric constant tensor. {∂_μ} is the basis of the tangent vector space over the underlying spacetime Now, from my understanding the enveloping algebra which appears in the definition of the Hopf algebra...

Similar threads

  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 18 ·
Replies
18
Views
4K
  • · Replies 14 ·
Replies
14
Views
4K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 25 ·
Replies
25
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K