Velocity, acceleration, and position graphs

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SUMMARY

The discussion focuses on understanding the relationship between position-time, velocity-time, and acceleration-time graphs for an object thrown vertically. The acceleration-time graph is characterized by a constant negative line due to the uniform acceleration of gravity at 9.8 m/s². The velocity-time graph can be derived using the equation v=at, while the position can be calculated using the appropriate kinematic equations. The participants emphasize the importance of recognizing that all objects fall at the same acceleration regardless of mass.

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  • Understanding of kinematic equations
  • Familiarity with graph interpretation in physics
  • Knowledge of constant acceleration concepts
  • Basic algebra for solving equations
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  • Study kinematic equations for motion under constant acceleration
  • Learn how to derive velocity and position equations from acceleration
  • Explore graphical analysis of motion in physics
  • Investigate the effects of different forces on acceleration
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Students studying physics, educators teaching motion concepts, and anyone interested in the graphical representation of kinematics.

Porcelain
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I have the answers, but I don't know how to get them.

The starting graph is a position-time graph of a basketball being thrown straight up into the air.
From that graph i have to find an acceleration-time graph, and a velocity-time graph.

Can someone explain to me the acceleration-time graph? why is it a constant negative line, if the graph of the position graph first goes up then down?

I think I understand how the velocity-time graph works with this.


My next question wants a graph of position vs. time, and a graph of velocity vs. time for an object moving with a constant negative acceleration.
again i have the answers, but I really don't know how to get to them.
thanks in advance for the explanations :)
 
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The acceleration-time graph is a line, which means acceleration remains constant. That's how gravity works; all objects, regardless of mass, fall at an acceleration of 9.8 m/s^2 down.

For your second question, try writing out the object's velocity in an equation; ditto for its position. v=at, and d=?
 
ideasrule said:
The acceleration-time graph is a line, which means acceleration remains constant. That's how gravity works; all objects, regardless of mass, fall at an acceleration of 9.8 m/s^2 down.

For your second question, try writing out the object's velocity in an equation; ditto for its position. v=at, and d=?

A horizontal line with a slope of zero, right?
 

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