Velocity and angular acceleration

Zeno's Paradox · 2006-11-18T14:08:07+00:00

Is this true? \vec \omega \times r = \vec v

Thread starter Zeno's Paradox
Start date Nov 18, 2006
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Acceleration Angular Angular acceleration Velocity

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SUMMARY

The discussion clarifies the relationship between angular velocity, position vector, and tangential velocity in physics. It establishes that the correct expression is \(\vec {\omega} \times \vec{r} = \vec{v}\), emphasizing the importance of referencing a fixed origin. The terms involved are angular velocity (\(\vec{\omega}\)), position vector (\(\vec{r}\)), and tangential velocity (\(\vec{v}\), which is derived from the cross product of angular velocity and position vector.

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Nov 18, 2006

Zeno's Paradox

Is this true?

[tex]\vec \omega \times r = \vec v[/tex]

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Nov 18, 2006

neutrino

That's actually meaningless.

This is true:[tex]\vec {\omega} \times \vec{r} = \vec {v}[/tex]

(with respect to fixed origin)

Assuming omega is the angular velocity, r position vector, and v, the tangential velocity.