1. The problem statement, all variables and given/known data If a 15kg object is released from a height of 11.58m and the objects loss in energy is 302 J, determine its velocity as it enters the container (object is being dropped straight down into a container) Assume g = 9.8m/s^2 m(object) = 15kg = w(object) = 147N s = 11.58m ΔE = -320 J 2. Relevant equations Had no idea. But the ones i know that i thought could apply: ΔKE = KE(final) - KE(initial) KE = 1/2 * mv^2 GPE = mgh v^2 = u^2 + 2as 3. The attempt at a solution Okay, I had no idea how to do this, but i tried to work out as many things as i can then mash em together to get an answer :p GPE = mgh =15*9.8*11.58 =1702.26 Then i thought; well if the loss in energy is 320 J then i could take that from the original GPE 1702.26 - 320 = 1382.26 J and now i could work out the new height by subbing it back in 1382.26 = 15*9.8*h h=9.403m And here is where it gets iffy... they say the velocity when it enters the container, but the container isn't at 9.403m its at 0...right? thats what i got from the question anyway. Therefore how did they only lose 320N? So I assumed that I could say its KINETIC energy is the 1382.26 J, and the height of the container is the difference because they say when it "enters". Therefore.. KE = 1/2 * m * v^2 1382.26 = 1/2 * 15 * v^2 2764.52 = 15 * v^2 v^2 = 184.30 v = 13.58 m/s We don't have the answer to this question yet, but *a lot* of other people got 13.66m/s as the answer... so since i had no idea how to do this question and no basis to support whether im right or not, could someone help me out and either point out where i went wrong or if I'm right? thank you!