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Velocity divided by Acceleration gives distance?

  1. Jun 24, 2016 #1
    See I figured that since Velocity = m/s
    Acceleration = m/s^2

    If I have velocity divided by Acceleration
    ----> m/s ÷ m/s^2 = s



    Relevant equations

    Velocity --> s/t
    Acceleration --> (v-u)/t



    The attempt at a solution
    My idea seems reasonable to me but somehow I couldn't apply this logic to related questions. Based on my understanding, velocity divided by acceleration gives distance as 's' but it don't seems applicable when I attempted questions with this approach.
     
  2. jcsd
  3. Jun 24, 2016 #2

    billy_joule

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    Science Advisor

    No it doesn't. You're mixing symbols with units, s is short for seconds. eg velocity is metres per second (m/s)
    In the kinematic equations (SUVAT) 's' is used to represent distance (which has units of metres)

    s is distance in metres (m)
    u is initial velocity in metres per second (m/s)
    v is final velocity in metres per second (m/s)
    a is acceleration in metres per second squared (m/s2)
    t is time in seconds (s)
     
  4. Jun 24, 2016 #3
    Oh wait... I see the mistake now oh my, hahaha! It is really stupid... *cringing*
    But thanks alot for the detailed explanation there, appreciate it really!

    Cheers!
     
  5. Jun 24, 2016 #4

    SteamKing

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    Staff Emeritus
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    Homework Helper

    That's only because the masses (m) canceled out. :rolleyes: o_O :confused:
     
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