- #1
Mongster
- 20
- 7
See I figured that since Velocity = m/s
Acceleration = m/s^2
If I have velocity divided by Acceleration
----> m/s ÷ m/s^2 = sRelevant equations
Velocity --> s/t
Acceleration --> (v-u)/tThe attempt at a solution
My idea seems reasonable to me but somehow I couldn't apply this logic to related questions. Based on my understanding, velocity divided by acceleration gives distance as 's' but it don't seems applicable when I attempted questions with this approach.
Acceleration = m/s^2
If I have velocity divided by Acceleration
----> m/s ÷ m/s^2 = sRelevant equations
Velocity --> s/t
Acceleration --> (v-u)/tThe attempt at a solution
My idea seems reasonable to me but somehow I couldn't apply this logic to related questions. Based on my understanding, velocity divided by acceleration gives distance as 's' but it don't seems applicable when I attempted questions with this approach.