Velocity divided by Acceleration gives distance?

[Mongster]

See I figured that since Velocity = m/s
Acceleration = m/s^2

If I have velocity divided by Acceleration
----> m/s ÷ m/s^2 = sRelevant equations

Velocity --> s/t
Acceleration --> (v-u)/tThe attempt at a solution
My idea seems reasonable to me but somehow I couldn't apply this logic to related questions. Based on my understanding, velocity divided by acceleration gives distance as 's' but it don't seems applicable when I attempted questions with this approach.

 

[billy_joule]

. Based on my understanding, velocity divided by acceleration gives distance as 's' .

No it doesn't. You're mixing symbols with units, s is short for seconds. eg velocity is metres per second (m/s)
In the kinematic equations (SUVAT) 's' is used to represent distance (which has units of metres)

s is distance in metres (m)
u is initial velocity in metres per second (m/s)
v is final velocity in metres per second (m/s)
a is acceleration in metres per second squared (m/s²)
t is time in seconds (s)

 

[Mongster]

Oh wait... I see the mistake now oh my, hahaha! It is really stupid... *cringing*
But thanks a lot for the detailed explanation there, appreciate it really!

Cheers!

 

[SteamKing]

See I figured that since Velocity = m/s
Acceleration = m/s^2

If I have velocity divided by Acceleration
----> m/s ÷ m/s^2 = sRelevant equations

Velocity --> s/t
Acceleration --> (v-u)/tThe attempt at a solution
My idea seems reasonable to me but somehow I couldn't apply this logic to related questions. Based on my understanding, velocity divided by acceleration gives distance as 's' but it don't seems applicable when I attempted questions with this approach.

That's only because the masses (m) canceled out.

 

[Dumisa Ngwenya]

Yes. s is correct. How long it takes to reach the velocity. "Long" being the "distance". It is something like a period vs frequency.

Don't confuse velocity x time = distance.

 

[topsquark]

Yes. s is correct. How long it takes to reach the velocity. "Long" being the "distance". It is something like a period vs frequency.

Don't confuse velocity x time = distance.

Ummmm... What? How long it takes to reach the velocity... from what starting point?

Mongster even admitted that they confused the s (distance) with the unit s (seconds.) The problem was already solved 7 years ago, no need to add to it.

-Dan