- #1
NTL01
- 21
- 3
Homework Statement
A 1.5 inch spring is .75 inches at solid length when fully compressed. The spring force is rated at 400 lbs per inch. A 3 kilogram mass will be pushed by the spring. What is the velocity of the mass at the instant the spring has fully decompressed. It will take the spring 1/20 of a second to decompress
2. Relevant equation
An equation was offered to me by a tutor as follows
V=(2F*t2)/3.14M
Where F is the force of the spring in Newtons, T2 is the time it takes for the spring to decompress , M is the mass being pushed
The Attempt at a Solution
I don't have any trouble solving this equation because I have all the variables. What troubles me is I don't think it makes intuitive sense because of the T2 term. The slower the spring decompresses the more the velocity goes up, which just doesn't seem logical
I am seeking comments , and possibly an alternative formula.
The formula above was derived by use of hooks law and the F=MA resolved into a differential equation, and I can't follow the derivation well enough to see if there was a mistake