An Earth satellite remains in orbit at a distance of 6104 km from the center of the Earth. What speed would it have to maintain? The universal gravitational constant is 6.67X10^-11 N m^2/kg^2. The mass of the earth it 5.88X10^24 kg. Answer in units of m/s. So again, missed the class. I'm crying. Most of my classmates are crying. (the few exceptions finding everything else to do in the world BUT help....) I tried this: I knew that it had to go into the equation: Vt=2piR/T since I didn't have T i used the equation: R= [(G x m x T^2)/(4pi)^2]^(1/3) sooo that became: 6104000m=[(6.67X10^-11)(5.98X10^24kg)(T^2)/(4pi)^2]^(1/3) (2.274X10^20)= (3.98866X10^14)(T^2)/(4pi)^2 T=9488.369sec so then plugging back in I got: Vt=(2pi)(6104000m)/9488.369sec thus the answer was 4042.06066 m/s guess what? That was wrong. If anyone has any ideas where I messed up or if I just had a "100% FAIL" moment, I would love to hear it.