- #1
BoldKnight399
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An Earth satellite remains in orbit at a distance of 6104 km from the center of the Earth. What speed would it have to maintain? The universal gravitational constant is 6.67X10^-11 N m^2/kg^2. The mass of the Earth it 5.88X10^24 kg. Answer in units of m/s.
So again, missed the class. I'm crying. Most of my classmates are crying. (the few exceptions finding everything else to do in the world BUT help...) I tried this:
I knew that it had to go into the equation:
Vt=2piR/T
since I didn't have T i used the equation:
R= [(G x m x T^2)/(4pi)^2]^(1/3)
sooo that became:
6104000m=[(6.67X10^-11)(5.98X10^24kg)(T^2)/(4pi)^2]^(1/3)
(2.274X10^20)= (3.98866X10^14)(T^2)/(4pi)^2
T=9488.369sec
so then plugging back in I got:
Vt=(2pi)(6104000m)/9488.369sec
thus the answer was 4042.06066 m/s
guess what? That was wrong.
If anyone has any ideas where I messed up or if I just had a "100% FAIL" moment, I would love to hear it.
So again, missed the class. I'm crying. Most of my classmates are crying. (the few exceptions finding everything else to do in the world BUT help...) I tried this:
I knew that it had to go into the equation:
Vt=2piR/T
since I didn't have T i used the equation:
R= [(G x m x T^2)/(4pi)^2]^(1/3)
sooo that became:
6104000m=[(6.67X10^-11)(5.98X10^24kg)(T^2)/(4pi)^2]^(1/3)
(2.274X10^20)= (3.98866X10^14)(T^2)/(4pi)^2
T=9488.369sec
so then plugging back in I got:
Vt=(2pi)(6104000m)/9488.369sec
thus the answer was 4042.06066 m/s
guess what? That was wrong.
If anyone has any ideas where I messed up or if I just had a "100% FAIL" moment, I would love to hear it.