1. The problem statement, all variables and given/known data A projectile is launched straight upward at +63.0 m/s from a height of 85.0 m, at the edge of a sheer cliff. The projectile falls, just missing the cliff and hitting the ground below. Maximum height = 202.5m 1) Find the time it takes to hit the ground at the base of the cliff. 2) Find its velocity at impact 2. Relevant equations xf=xi+vit+1/2at2 vf=vi+at 3. The attempt at a solution For #1 I tried this: xi=202.5 xf=0 a=-9.80 vi=0 0=202.5+0+1/2(-9.8)t2 -202.5=-4.9t2 41.327=t2 t=6.429 But that's not the right answer For #2 I tried this: (It depends on the answer to #1) Vf=0+(-9.8)(6.429) Vf=-63.004 But that's wrong too since #1 is wrong. What did I do wrong in #1?