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Velocity of a ladybug relative to the ground

  1. Apr 13, 2012 #1
    1. The problem statement, all variables and given/known data
    A ladybug with a velocity of 10 mm/s [W] crawls on a chair that is being pulled with a velocity of 40 mm/s [40 degrees N of W]. What is the velocity of the ladybug relative to the ground?


    2. Relevant equations



    3. The attempt at a solution
    finding the y-component
    40(sin40) = 25.7

    x-component requires the addition of two x-axis component vectors
    40cos40 + 10 = 40.6

    Now a² + b² = c²
    25.7² + 40.6² = c²
    c = 48.1mm/s
     
  2. jcsd
  3. Apr 13, 2012 #2

    tiny-tim

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    Hi TheronSimon! :smile:
    looks ok :smile:

    now you just need to state the direction of the velocity :wink:

    (btw, maximum 2 significant figures in this case :wink:)
     
  4. Apr 14, 2012 #3
    so for the direction tan -1 (25.7/40.6) = 32'

    so the complete answer is 48 mm/s [W32'N] ?
     
  5. Apr 14, 2012 #4

    tiny-tim

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    yes :smile:

    (probably best to call it "32° N of W", same as in the question :wink:)

    (btw, you'll find a ° in the Quick Symbols box on the right of the Reply box)
     
  6. Apr 14, 2012 #5
    alright thank you very much Tim! :)
     
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