The problem reads:
"Hockey puck A sliding on ice with velocity 10 m/s in the x direction collides at a glancing blow with a second stationary puck B. Puck A scatters at an angle of θA= 40 degrees above the x axis, while B slides away at an angle ofθB= 50 degrees below the x axis. (a) Use momentum conservation to find the final speeds vA and vB of the two pucks, respectively. What is the change in kinetic energy? (b) What are the two scattering angles according to an observer in the center of mass frame of reference?"
mAv1A + mBv1B = mAv2A + mBv2B
The Attempt at a Solution
Ok, so far I divided the problem into x and y components, where the final velocities in the x direction would be v2Acos40 and v2Bcos50 and the final velocities in the y direction would be v2Asin40 and -v2Bsin50. I feel like there are too many unknowns, we aren't given the masses of the two pucks, and I have absolutely no clue how to do this problem without the masses of the pucks. I have 4 unknowns (final velocities and the masses) and only two equations. Am I missing something??? How do I approach this problem??