Velocity of a proton after accelerated through potential

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SUMMARY

A proton accelerated from rest through a potential difference of 6.3 × 105 V achieves a final speed calculated using the work-energy principle. The relevant formula is W = qV, where W represents work, q is the charge of the proton, and V is the potential difference. The kinetic energy (KE) gained by the proton is equal to the work done by the electric field. The mass of the proton is 1.673 × 10-27 kg, which is essential for determining the final speed in meters per second.

PREREQUISITES
  • Understanding of basic physics concepts, particularly kinetic energy.
  • Familiarity with electric potential and work-energy principles.
  • Knowledge of the charge of a proton (approximately 1.602 × 10-19 C).
  • Ability to perform calculations involving mass and velocity.
NEXT STEPS
  • Calculate the final speed of a proton using the formula v = √(2qV/m).
  • Explore the relationship between electric potential and kinetic energy in particle physics.
  • Learn about the implications of accelerating charged particles in electric fields.
  • Investigate other applications of the work-energy principle in different contexts.
USEFUL FOR

Students studying physics, particularly those focusing on electromagnetism and particle dynamics, as well as educators seeking to clarify concepts related to electric potential and kinetic energy.

Taryn
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hey Hoping that someone could possibly help me start this problem... I don't know which formula to use... maybe something to do with Kinetic energy... but like I said I am not sure how to start this problem!
Thanks for your time... here is the question!

A proton is accelerated from rest through a potential of 6.3 × 105 V. What is its final speed in m/s? (mp = 1.673 × 10-27 kg.)

Its really simple I know but for someone reason it has me stumped
 
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Hint: W = qV
where V is p.d and q the charge.
The work done by the p.d is converted to the KE of the particle.
 
thanks I think me got the answer now thanks!
 

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