Lorentz momentum: A proton of mass m is accelerated up

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SUMMARY

The discussion focuses on the relativistic collision of two protons, where one proton of mass "m" is accelerated to a kinetic energy "K" before colliding with a stationary proton. The key equations involved are the energy-momentum relationship, represented as E² = p²c² + m²c⁴, and the relativistic momentum p = γmv. The maximum mass "M" of the new particle created from the collision can be determined using conservation of momentum and energy principles, emphasizing the need to utilize relativistic expressions rather than Newtonian ones.

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squelch
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Homework Statement


A proton of mass "m" is accelerated up to a kinetic energy "K" and then collides with a stationary proton at rest. All that is left after the collision is a new particle of mass "M".
(a) Write out the momentum and energy equations for the collision.
(b) What is the maximum mass M that can be created in this collision?

Homework Equations



I'm not quite sure what to use here. I have:

\begin{array}{l}<br /> {E^2} = {p^2}{c^2} + {m^2}{c^4}\\<br /> p = \gamma mv<br /> \end{array}

The Attempt at a Solution



It seems like what I'm supposed to do is use the energy-momentum relationship and the formula for kinetic energy in this way:

\begin{array}{l}<br /> {(K - m{c^2})^2} = {p^2}{c^2} + {m^2}{c^4}\\<br /> K - m{c^2} = \sqrt {{p^2}{c^2} + {m^2}{c^4}}<br /> \end{array}

From here, do I use K = \frac{1}{2}m{v^2} to put together the p=mv relationship?

edit: I'm supposing that what I'm supposed to do here is solve for v somehow.
 
Last edited:
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squelch said:

Homework Statement


A proton of mass "m" is accelerated up to a kinetic energy "K" and then collides with a stationary proton at rest. All that is left after the collision is a new particle of mass "M".
(a) Write out the momentum and energy equations for the collision.
(b) What is the maximum mass M that can be created in this collision?

Homework Equations



I'm not quite sure what to use here. I have:

\begin{array}{l}<br /> {E^2} = {p^2}{c^2} + {m^2}{c^4}\\<br /> p = \gamma mv<br /> \end{array}

The Attempt at a Solution



It seems like what I'm supposed to do is use the energy-momentum relationship and the formula for kinetic energy in this way:

\begin{array}{l}<br /> {(K - m{c^2})^2} = {p^2}{c^2} + {m^2}{c^4}\\<br /> K - m{c^2} = \sqrt {{p^2}{c^2} + {m^2}{c^4}}<br /> \end{array}

From here, do I use K = \frac{1}{2}m{v^2} to put together the p=mv relationship?

edit: I'm supposing that what I'm supposed to do here is solve for v somehow.
You can't use the Newtonian expressions for the kinetic energy and momentum. You have to use the relativistic expressions.

A word of advice: Write your equations in terms of energies, momenta, and the masses. Your variables should be E's, p's, and m's, like in the first relevant equation you wrote above.

Before the collision, you have the energy and momentum of the first proton and the energy and momentum of the second proton. After the collision, you have the energy and momentum of the new particle. Assign a variable to each of those quantities and then write down the equations for conservation of momentum and energy.
 

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