What is the speed of a proton that has been accelerated from rest through a potential difference of -1000V?
Conservataion of energy
U=qEd (d is distance the proton is moving...i think)
The Attempt at a Solution
Here is my thought process with this problem:
ΔV=-1000V this means the change in electric potential is (-), doesnt tell us what V(initial) or V(final) is, but we know the difference between them is 1000
I know that V=U/q
For the proton going through this potential difference it follows conservation of energy:
here is where I get stuck...
it looks to me like we have one equation and two unknowns
the equation being:qEd=1/2mpv2
the unknowns: E and v
And I guess Im not even sure if Uf=0.