Velocity of the car as a function of time

Click For Summary
SUMMARY

The discussion centers on deriving the velocity function of a car with a mass of 1250 kg, accelerated by a constant power of 135 kW. The derived formula for velocity as a function of time is v(t) = sqrt(2Pt/m). The conversation also explores the implications of non-zero initial velocity on this formula, emphasizing the relationship between power, energy, and acceleration. Key equations referenced include P = W/t and V = P/F, which are critical for understanding the dynamics involved.

PREREQUISITES
  • Understanding of basic physics concepts such as power, energy, and force.
  • Familiarity with the equations of motion and their applications.
  • Knowledge of calculus, particularly in relation to derivatives and integrals.
  • Ability to manipulate algebraic expressions and solve for variables.
NEXT STEPS
  • Study the derivation of energy equations in physics, focusing on kinetic and potential energy.
  • Learn about the effects of initial conditions on motion equations, particularly in non-linear dynamics.
  • Explore the relationship between power, work, and energy in mechanical systems.
  • Investigate the implications of air resistance and friction on velocity equations in real-world scenarios.
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators and anyone interested in the principles of motion and energy transfer in vehicles.

dan_and_sim
Messages
2
Reaction score
0

Homework Statement


A car of mass m = 1250 kg is accelerated from rest by a constant power
P = 135 kW. The car is moving along a straight line.
Neglecting air resistance and friction, show that the velocity of the car
as a function of time is given by v(t) = sqrt 2Pt/m

then How would this change if the initial velocity was not equal to 0

Homework Equations


P=w/t
V=P/f



The Attempt at a Solution


Whats confusing me here is the sqrt and the m, i would of assumed that it should be ma as its v=P/f
 
Physics news on Phys.org


So a constant power is supplied. How much energy is supplied in a time t? Where does the energy from the power supplied go? If you know these, you should be able to get the required expression.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
3
Views
7K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
6K
  • · Replies 9 ·
Replies
9
Views
2K