Velocity of Waves in Liquid: Relation with Wavelength, γ & ρ

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SUMMARY

The velocity of waves in a liquid is directly influenced by the wavelength (λ), surface tension (γ), and density (ρ) of the liquid. The derived relationship indicates that the equation for wave velocity (v) must incorporate these variables in a manner that allows for unit cancellation, specifically placing either surface tension or density in the denominator. The fundamental units involved are meters for wavelength, Newtons per meter for surface tension, and kilograms per cubic meter for density. The final expression for velocity is confirmed to be in meters per second (m.s-1).

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  • Understanding of wave mechanics
  • Familiarity with fundamental physical units
  • Knowledge of surface tension and its formula
  • Basic algebra for unit manipulation
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  • Study the derivation of wave equations in fluids
  • Learn about the effects of surface tension on wave propagation
  • Explore the relationship between density and wave speed in different mediums
  • Investigate advanced fluid dynamics concepts related to wave behavior
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Students and professionals in physics, fluid dynamics researchers, and engineers working with wave phenomena in liquids.

ahmedb
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The velocity of waves in a liquid depends on the wavelength λ, surface tension γ, and density ρ, of the liquid, Derive an equation to relate v, with wavelength, surface tension and density, (note: surface tension, has a formula of force per unlit length and SI unit of Nm^-1)
 
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ahmedb said:
The velocity of waves in a liquid depends on the wavelength λ, surface tension γ, and density ρ, of the liquid, Derive an equation to relate v, with wavelength, surface tension and density, (note: surface tension, has a formula of force per unlit length and SI unit of Nm^-1)

reducing to fundamental units

λ - m
γ - N.m-1 = kg.m.s-2.m-1 = kg.s-2
ρ - kg.m-3

The final answer is velocity, so m.s-1

If you multiply all three together [ie λ x γ x ρ] we have m x kg.s-2 x kg.m-3 = kg2.s-2.m-2

Not quite what we wanted. We needed the kg to cancel out, so one of γ or ρ needed to be in the denominator.

The fact that all units were squared doesn't matter - we can throw in a √ at the end to fix that.

have a play round and see how you get on.
 

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