# Velocity squared vs position graph

1. Sep 5, 2008

### azn4lyf89

I calculated a slope from a best fit line of a velocity squared vs position graph but I don't understand what this slope represents. My units come out to be in cm/seconds squared, so does that mean thats my acceleration? It seems to be way off from 9.80m/sec^2 which should be my acceleration. Or does this slope help me determine to acceleration?

2. Sep 5, 2008

### rock.freak667

Well from $v^2=u^2+2as$

3. Sep 5, 2008

### azn4lyf89

Isn't that only if the graph was velocity squared vs time? Because s is seconds right?

4. Sep 5, 2008

### rock.freak667

s is displacement.

t is usually used to inidicate time.