The discussion revolves around interpreting the slope of a velocity squared versus position graph in the context of kinematics. The original poster questions the meaning of the slope and its relation to acceleration, particularly in light of expected values for gravitational acceleration.
The discussion is active, with participants providing insights into the interpretation of the slope and questioning the assumptions made about the variables in the equation. There is no clear consensus yet, as different interpretations of the graph's axes are being explored.
Participants are navigating potential misunderstandings regarding the definitions of the variables in the kinematic equation, particularly the use of 's' for displacement versus time. The original poster's units of measurement also raise questions about consistency and accuracy in their calculations.
rock.freak667 said:Well from v^2=u^2+2as
If you plot v2 vs. s, your gradient should be 2a
azn4lyf89 said:Isn't that only if the graph was velocity squared vs time? Because s is seconds right?