Velocity squared vs position graph

[azn4lyf89]

I calculated a slope from a best fit line of a velocity squared vs position graph but I don't understand what this slope represents. My units come out to be in cm/seconds squared, so does that mean that's my acceleration? It seems to be way off from 9.80m/sec^2 which should be my acceleration. Or does this slope help me determine to acceleration?

 

[rock.freak667]

Well from $v^2=u^2+2as$

If you plot v² vs. s, your gradient should be 2a

 

[azn4lyf89]

Well from $v^2=u^2+2as$

If you plot v² vs. s, your gradient should be 2a

Isn't that only if the graph was velocity squared vs time? Because s is seconds right?

 

[rock.freak667]

Isn't that only if the graph was velocity squared vs time? Because s is seconds right?

s is displacement.

t is usually used to inidicate time.