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Velocity squared vs position graph

  1. Sep 5, 2008 #1
    I calculated a slope from a best fit line of a velocity squared vs position graph but I don't understand what this slope represents. My units come out to be in cm/seconds squared, so does that mean thats my acceleration? It seems to be way off from 9.80m/sec^2 which should be my acceleration. Or does this slope help me determine to acceleration?
     
  2. jcsd
  3. Sep 5, 2008 #2

    rock.freak667

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    Well from [itex]v^2=u^2+2as[/itex]

    If you plot v2 vs. s, your gradient should be 2a
     
  4. Sep 5, 2008 #3
    Isn't that only if the graph was velocity squared vs time? Because s is seconds right?
     
  5. Sep 5, 2008 #4

    rock.freak667

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    s is displacement.

    t is usually used to inidicate time.
     
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