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Velocity,time,acceleration question

  1. Apr 17, 2009 #1
    A blue car moving at constant speed of 10m/s passes a polic car that is at rest. The police car accelerates from rest at 4m/s^2 for 3.0 seconds and then maintains a constant speed. The blue car maintains constant speed for the entire 12 seconds. When does the police car pass the blue car?

    Calculations:
    Blue Car:
    Vi= 10 m/s
    Vf = 10 m/s
    deltaT = 12 s
    deltaD = 120 m
    acceleration = 0

    Police Car:
    Vi = 0m/s
    acceleration = 4m/s^2 (for the first 3 seconds)
    deltaD (for first three seconds) = 18 m
    Vf = 12 m/s

    So when the deltaD of the blue car = the deltaD of the police car, the police car is at the same distance as the blue car.

    How would I go about doing this?
     
  2. jcsd
  3. Apr 17, 2009 #2

    CompuChip

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    Science Advisor
    Homework Helper

    Note how this problem is similar to this question.
    Probably if you solve the other one, you will be able to do this one yourself.
     
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