MHB How Do Truth Tables and Venn Diagrams Verify Logical Equivalence?

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To demonstrate the logical equivalence of the statements p v (q ^ r) and (p v q) ^ (p v r) using a truth table, one must fill out the truth values for all combinations of p, q, and r. The truth table shows that both expressions yield identical results across all scenarios, confirming their equivalence. In contrast, the expression (p v q) ^ r does not match the truth values of the first two statements, indicating that it is not logically equivalent. Venn diagrams can also illustrate these relationships visually, highlighting the overlaps and distinctions between the sets represented by the statements. This analysis effectively verifies logical equivalence through both truth tables and Venn diagrams.
barbara
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How would I use a truth table to show that the statement p v (q ^ r) is equivalent to (p v q) ^ (p v r) or design a venn diagram for this. and show that this statement is not equivalent to (p v q) ^ r.
 
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A truth-table might begin like this:

$\begin{array}{cccccccc}

P&Q& R&Q\wedge R&P\vee(Q\wedge R)& P\vee Q& P\vee R& (P\vee Q)\wedge(P\vee R)\\
\ast&\ast&\ast&\ast&\ast&\ast&\ast&\ast\\
T&T&T&T&T&T&T&-\\
T&T&F&F&T&T&T&-\\
T&F&T&F&T&T&T&-\\
T&F&F&F&T&T&T&-\\
F&T&T&T&T&T&T&-\\
F&T&F&F&F&T&F&-\\
F&F&T&F&F&F&T&-\\
F&F&F&F&F&F&F&-\\

\end{array}$

Your goal, then, is to fill out column 8, and verify it matches column 5...
 
The standard _A " operator" maps a Null Hypothesis Ho into a decision set { Do not reject:=1 and reject :=0}. In this sense ( HA)_A , makes no sense. Since H0, HA aren't exhaustive, can we find an alternative operator, _A' , so that ( H_A)_A' makes sense? Isn't Pearson Neyman related to this? Hope I'm making sense. Edit: I was motivated by a superficial similarity of the idea with double transposition of matrices M, with ## (M^{T})^{T}=M##, and just wanted to see if it made sense to talk...

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