- #1
fonz
- 151
- 5
Just simply, from the diagram above is p1=p3 and v1=v3?
Thanks
Dan
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In the context of the Venturi Principle, if viscosity is negligible and the cross-sectional areas are equal, then p1 equals p3 and v1 equals v3. However, the diagram does not confirm that A1 equals A3, which is crucial for this conclusion. In inviscid flow, the flow characteristics at section 3 cannot be definitively determined without knowing the diameter of that section. It is possible for the flow in section 3 to remain stationary while section 2 continues to flow at v2. Therefore, while mass flow remains constant, the average net flow v3 should match v1 only if the diameters of sections 1 and 3 are the same.
Just simply, from the diagram above is p1=p3 and v1=v3?
Thanks
Dan
- #2
MrRobotoToo
- 110
- 50
If the viscosity is negligible, then yes.
- #3
cjl
Science Advisor
- 2,001
- 612
If the cross sectional areas are the same and the flow is inviscid, then yes. From the diagram, it isn't certain that A1 = A3 though.
- #4
rcgldr
Homework Helper
- 8,938
- 686
If the flow is inviscid, then the inner flow at section 3 can't be determined. With zero viscosity, there's no reason that the flow from section 2 couldn't simply continue with the same diameter as the tube in section 2, flowing at v2 while the surrounding fluid in section 3 isn't moving at all, since there's no interaction between shear boundaries with an inviscid flow. The "average" net flow v3 should be the same as v1 since mass flow is constant, assuming section 3 diameter is the same as section 1 diameter.cjl said: