LaTeX Help Me Understand Latex Derivatives: Struggling With Calculus After 2 Years

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SUMMARY

The discussion focuses on the challenges faced by a user in understanding derivatives in the context of differential equations (DE) after a two-year hiatus from calculus. The user presents the equation y=2xy1+y(y1)² and the derived solution y2=C1(x+1/4C1), expressing confusion over the implicit differentiation process that leads to y1=C1/2y. The user struggles to verify the solution by substituting the derivative back into the original differential equation, indicating a need for clarity in the differentiation and verification process.

PREREQUISITES
  • Understanding of implicit differentiation
  • Familiarity with differential equations (DE)
  • Basic knowledge of calculus, specifically derivatives and integrals
  • Proficiency in LaTeX for mathematical notation
NEXT STEPS
  • Study implicit differentiation techniques in calculus
  • Review the principles of verifying solutions to differential equations
  • Practice LaTeX formatting for mathematical expressions
  • Explore examples of solving and checking differential equations
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Students in calculus or differential equations courses, educators teaching these subjects, and anyone looking to refresh their understanding of derivatives and their applications in differential equations.

ae4jm
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Sorry it's not the best Latex, I hope that you can still help me grasp this.

Code:
y=2xy[SUP]1[/SUP]+y(y[SUP]1[/SUP])[SUP]2[/SUP]; y[SUP]2[/SUP]=C[SUB]1[/SUB](x+1/4C[SUB]1[/SUB])

So, the solution says to implicitly differentiate and gives
Code:
y[SUP]1[/SUP]=C[SUB]1[/SUB]/2y

So, how did they get the derivative to be this? This is the first chapter in my DE class and I'm rusty with my integrals and derivatives, been about 2 years since my calc classes.

Thanks for any help...
 
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First, it that really what they have? Is there a reason for writing "y(y^2)^2 rather than just y^5?
 
In my latex from my previous post it is actually supposed to be y prime where y is raised to the first power. But yes, this is how it was in the textbook...

Thanks for your reply...
 
Okay, I figured the derivative of
Code:
y[SUP]2[/SUP]=C[SUB]1[/SUB](X+(1/4)C[SUB]1[/SUB])
to be
Code:
 dy/dx=C[SUB]1[/SUB]/2y

But, now I can't verify the solution by plugging the derivative back into the equation, I can't get both sides equal to each other, which is what the problem is asking for. A differential equation with a solution was given; I'm supposed to find the derivative of the solution and plug it back into the differential equation to prove that the solution is actually a correct answer.

Any help? I tried plugging the derivative back into the DE and I've tried solving the solution for y and plugging that and the derivative back into the original DE but I've had no luck setting each other equal to the other. This is the same thing as solving a DE and checking your work but I can't get them to equal each other.

Thanks for any help or recommendations...
 
Please, can you guys offer me any guidance? After I find the derivative and plug it into the original DE and I solve the solution for y and plug it into the original DE I'm not getting the solution to be correct.
 

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