Verifying Proton Removal from Sn and Sb Nuclei

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SUMMARY

The discussion focuses on verifying the removal of protons from the Sn (Tin) and Sb (Antimony) nuclei, specifically addressing the energy required for this process. Sn has a filled proton shell with a magic number of 50, while Sb has an additional proton, making it 51. According to the shell model, the extra proton in Sb should be easier to remove than one from the filled shell of Sn. The participants suggest calculating the binding energy using the provided atomic masses: Sn (119.902199 u) and Sb (120.903821 u), along with the mass of a hydrogen atom (1.007825 u).

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kidia
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Hi can anybody help me on this I really need it.

The nuclide Sn has a filled proton shell, 50 being on one of the magic nucleon number. Sb has an extra proton outside this shell to make 51. According to the shell model, extra proton should be easier to remove than a proton from the filled shell. Verify this by calculating the required energy in each case.
Sn mass 121 Atomic Mass (u) 119.902199
Sb mass 120 Atomic Mass (u) 120.903821

Mass of hydrogen atom is 1.007825u.
 
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This is basically a binding energy calculation.

Correction - Sn mass 120 Atomic Mass (u) 119.902199

Start by writing the equations which show the reaction.

ZXA -> 1H1 + Z-1YA-1

then calculate the binding energy accordingly.

Useful reference - http://wwwndc.tokai.jaeri.go.jp/CN04/CN012.html

http://wwwndc.tokai.jaeri.go.jp/CN04/index.html
 
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