Vertex of a Function: -3(x-2)^2-3

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SUMMARY

The vertex of the function f(x) = -3(x-2)² - 3 is definitively located at the point (2, -3). This conclusion arises from the vertex formula, which indicates that the vertex is determined by the expression (x-h), where h represents the x-coordinate of the vertex. In this case, substituting x = 2 results in f(2) = -3, confirming that (2, -3) is the maximum point on the graph, as any deviation from this x-value yields a lower function value.

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Drakkith
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I have the following function and I'm supposed to find the vertex of its graph.

f(x)=-3(x-2)2-3

Why is the vertex (2,-3) instead of (-2,-3)?

Edit: Bah, nevermind. I just realized the formula has (x-h) in it, not (x+h) in it...
 
Last edited:
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Do you understand why the formula for vertex involves x- h, not x+ h?

The crucial point is that if x= 2, (x- 2) will be 0 so that f(2)= -3. If x is any other number (including -2) x- 2 will NOT be 0 so that, because the square of any non-zero number is positive, -3(x-2)^2 will be negative and f(x)= -3(x- 2)^2- 3 will be lower than three. (2, -3) is the highest point on the graph.
 

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