The original poster attempts to find the vertex of the parabola defined by the equation y² - 12 = 12x. The problem involves understanding the properties of parabolas and their standard forms.
Some participants have offered hints and suggestions regarding the approach to take, while others have shared their own attempts at solving the problem. The discussion reflects a mix of exploration and clarification of concepts without reaching a definitive conclusion.
There is a note about the importance of showing work in future posts, indicating a focus on the learning process and the need for clearer communication of attempts.
You could have made a sketch of this equation in about 5 minutes and figured out where the vertex is located.Sarah Kenney said:Homework Statement
I'm trying to find the vertex of this parabola: y^2-12=12x
The Attempt at a Solution
Initially I tried to take the derivative and find the vertex by finding where it the function is zero, but apparently that does not work in this situation. Is it because it is not in standard form? I've been staring at this problem for hours. I need a hint.
Thanks.
In future posts, please show what you have tried, rather than describe it.Sarah Kenney said:Ok, so I figured it out.
It's:
y^2=12x+12
y^2=12(x+1)
x=-1
So y= 0
I don't know why that took me so long. Math brain.
Thanks.