Vertical motion with constant acceleration

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SUMMARY

The discussion centers on calculating the amount of ballast required to change the acceleration of a research balloon from downward to upward. The balloon, with a total mass of 410 kg, is initially descending at 1.0 m/s². To achieve an upward acceleration of 1.6 m/s², the calculations reveal that approximately 201.2 kg of ballast must be discarded. The key equations utilized include B - w = m * a and w = mg, with the weight calculated as w = 4018 N.

PREREQUISITES
  • Understanding of Newton's second law of motion
  • Familiarity with gravitational force calculations
  • Basic algebra for solving equations
  • Knowledge of forces acting on objects in vertical motion
NEXT STEPS
  • Study advanced applications of Newton's laws in varying contexts
  • Learn about buoyancy and its effects on objects in fluid dynamics
  • Explore the principles of vertical motion under different acceleration scenarios
  • Investigate the impact of mass changes on acceleration in practical applications
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Students in physics, engineers working with aerodynamics, and anyone involved in ballooning or vertical motion dynamics will benefit from this discussion.

Kajayacht
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Homework Statement


A research balloon of total mass 410 kg is descending vertically with a downward acceleration of 1.0 m/s2. How much ballast must be thrown from the car to give the balloon an upward acceleration equal to 1.6 m/s2, presuming that the upward lift of the balloon does not change.


Homework Equations


B-w=m*a
w=mg

The Attempt at a Solution



w= 410*9.8
w= 4018 N

B-4018 = 410*-1
B=3608

3608-m{2}*9.8= m{2}*1.6
2255= m{2}+9.8m{2}
2255= 10.8m{2}
m{2} = 208.80
410-208.80= 201.2kg
 
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Kajayacht said:

Homework Statement


A research balloon of total mass 410 kg is descending vertically with a downward acceleration of 1.0 m/s2. How much ballast must be thrown from the car to give the balloon an upward acceleration equal to 1.6 m/s2, presuming that the upward lift of the balloon does not change.


Homework Equations


B-w=m*a
w=mg

The Attempt at a Solution



w= 410*9.8
w= 4018 N

B-4018 = 410*-1
B=3608

3608-m{2}*9.8= m{2}*1.6
2255= m{2}+9.8m{2}your algebra is wrong. Should be 3608 = 11.4m{2}[/color]
2255= 10.8m{2}
m{2} = 208.80
410-208.80= 201.2kg
Your method is good. Check your math error as noted above.
 

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