motivehunter
- 12
- 1
Hi!
In a speed-reduction drive, because the power transmitted is almost constant, as the speed decreases the torque increases. Is this reduced rear wheel/shaft speed the same when the loaded condition is considered?
Let's assume that the prime mover is rated to produce 1.4 mN torque at 2700 rpm by the manufacturer. Using a reduction ratio of 27:1, our rear wheel velocity would be 100 rpm and torque would be 37.8 mN. My question is, when the prime mover is loaded, does it still make the rear wheel rotate at 100 rpm or at a much lower speed?
I'm sorry for posting such a simple question but its one of those things about which i can't seem to think too clearly!
Thanks!
In a speed-reduction drive, because the power transmitted is almost constant, as the speed decreases the torque increases. Is this reduced rear wheel/shaft speed the same when the loaded condition is considered?
Let's assume that the prime mover is rated to produce 1.4 mN torque at 2700 rpm by the manufacturer. Using a reduction ratio of 27:1, our rear wheel velocity would be 100 rpm and torque would be 37.8 mN. My question is, when the prime mover is loaded, does it still make the rear wheel rotate at 100 rpm or at a much lower speed?
I'm sorry for posting such a simple question but its one of those things about which i can't seem to think too clearly!
Thanks!