Very Quick Differentiation Question

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The discussion centers on differentiating the equation c2 = a2 + b2 - 2ab cos(θ) with respect to variable b. The user initially misapplied differentiation rules, confusing the treatment of cos(θ) as a constant rather than a function of b. The correct approach requires recognizing that if θ is not a function of b, cos(θ) remains unchanged during differentiation. The user acknowledges the need for clearer mathematical notation in forum discussions.

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First I attempted to ipmlicitly differentiate
c2 = a2 + b2 -2abcos(theta)

da/db


I almost got the correct solution according to MIT's key, however I missed one part. The cos from the original function remained cos, and I had differentiated it to -sin.

I'm just wondering why it remained cos instead of being differentiated?
 
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Unless theta is a function of b, then cos(theta) is a constant when trying to find the derivative with respect to b.
 
It's very difficult to read what you have written. Are those "2"s after the letters squares? If you cannot use use LaTeX, c^2= a^2+ b^2- 2ab cos(\theta), at least use "^" to indicate powers: c^2= a^2+ b^2- 2ab cos(theta).

But the real question is "differentiate what variable with respect to what other variable?"
 
Thanks, but SteamKing already helped solve my problem.. Sorry I will be sure to start using the forums code based mathematical notation from now on.
 

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