Vibration Problem with Fixed End Beam and Unbalanced Motor | Homework Help

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The discussion revolves around a fixed-end beam with an unbalanced motor causing vibrations that match the motor's rotational speed. When the motor operates at 120-150 rpm, a mass placed on the beam loses contact and "dances" due to these vibrations. Participants clarify that the motor speed corresponds to the frequency of the beam's vibration, specifically referring to angular speed. The problem requires determining the amplitude of vibration at both 120 rpm and 150 rpm, as well as calculating the system's natural frequency. The urgency for assistance highlights the complexity of finding the natural frequency in this base excitation scenario.
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vibration problem!

Homework Statement



Question:There is a fixed end beam PQ. It is carrying a motor M. The motor is unbalanced and when the motor is rotating ,it is making the beam to vibrate with a frequency equal to the speed of the motor. A small mass is kept at point A just above the motor on the beam. it also goes up & down along with the beam . When the motor speed is 120 - 150rpm, the object at A is loosing contact with the beam & is actually dancing on the beam. Determine the amplitude of vibration when the speed of motor is 120 rpm and when 150 rpm . Then calculate the natural frequency of the system.

|---------------------M--------------------|

data may be suitably assumed.


Homework Equations



can't get any of them

The Attempt at a Solution



This is a base excitation problem. but the natural frequency is diff. to find. pls help
 

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bikramjit das said:
The motor is unbalanced and when the motor is rotating ,it is making the beam to vibrate with a frequency equal to the speed of the motor

which speed are we talking about here?
 


@cupid: u can assume the speed of motor as N. This is equal to the frequency of vibration of beam (base).
 


i mean ... are we talking about angular speed?
 


yeah, angular speed...pls solve it quickly, grave need
 


heyy...some one help me out with this question
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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