Violin frequencies and harmonics

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SUMMARY

The discussion focuses on the physics of violin strings, specifically the A and D strings tuned to 440 Hz and 294 Hz, respectively. The fundamental wavelength of the A string is calculated as 0.64 m, while the wavelength of the D string when played is 1.17 m. The third harmonic frequency of the D string is determined to be 882 Hz, and the second harmonic frequency of the A string is 880 Hz, resulting in a beat frequency of ±2 Hz. The calculations utilize the wave equations for strings and sound propagation in air.

PREREQUISITES
  • Understanding of wave equations: f_n = n(v/2L) and λ_n = 2L/n
  • Knowledge of sound velocity in air (343 m/s)
  • Familiarity with harmonic frequencies and overtones
  • Basic principles of string instruments and their tuning
NEXT STEPS
  • Explore the relationship between string length and frequency in string instruments.
  • Learn about the physics of sound waves and their propagation in different mediums.
  • Investigate the concept of beat frequencies in acoustics.
  • Study the harmonic series and its application in musical tuning systems.
USEFUL FOR

Musicians, acoustics students, physics enthusiasts, and anyone interested in the principles of sound production in string instruments.

toothpaste666
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Homework Statement


A violin has four strings that are 32 cm long and are typically tuned to concert G, D, A, and E (196 Hz, 294 Hz, 440 Hz, and 660 Hz).

A)What is the wavelength of the fundamental mode of oscillation on the A string?
Sketch the waveform.

B)What is the wavelength of the sound in air when the D string is played (at 294 Hz)?
Assume that the velocity of sound in air is 343 m/s.

C)Calculate the frequency of the third harmonic (second overtone) on the D string
and the second harmonic (first overtone) on the A string. You will find that the
harmonics have similar frequencies. What is the beat frequency between the two
harmonics?

Homework Equations


f_n = n(v/2L)
(lamba_n) = 2L/n

The Attempt at a Solution


A) for the fundamental wavelength
lambda = 2L = 2(.32m) = .64 m
the picture is one standing wave over the length of the string

B) v= lambda * f
lambda = v/f = 343/294 = 1.17 m

C) for the D string. to find v we use the fundamental frequency
f = v/2L
294 Hz = v / .64m
v = .64 (294) = 188.16
for the third harmonic
f_3 = 3(v/2L) = 3(188.16/.64) = 882 Hz

for for A string
fundamental
f = v/2L
440 = v / .64
v = .64(440) = 281.6
second harmonic
f_2 = 2(281.6/.64) = 880 Hz

so the beat frequency is +/- 2 Hz
 
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Your solution looks correct to me. Although for part C you could have found the frequencies of the Nth harmonic easier by just multiplying the fundamental frequency by N.
 
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Likes   Reactions: toothpaste666
ah yeah you are right. thank you!
 

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